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Oracle 1z0-071 Torrent & 1z0-071 Reliable Test Review

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Oracle Database SQL Sample Questions (Q234-Q239):

NEW QUESTION # 234
Examine the description of the ORDERS table:

Which three statements execute successfully?

A. SELECT order_ id, invoice_ data order_ date FROM orders
MINUS
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY invoice_ id;
B. SELECE order _id, order _ date FRON orders
LNTERSECT
SELECT invoice_ id, invoice_ id, order_ date FROM orders
C. SELECT * FROM orders ORDER BY order_ id
INTERSEOT
SELECT * FROM invoices ORDER BY invoice_ id;
D. SELECT * FROM orders
MINUS
SELECT * FROM INVOICES ORDER BY 1
E. SELECT * FROM orders ORDER BY order_ id
UNION
SELECT * FROM invoices;
F. SELECT order_ id, order_ data FROM orders
UNION ALL
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY order_ id;
G. (SELECT * FROM orders
UNION ALL
SELECT* FROM invoices) ORDER BY order _id;

Answer: E,F,G

Explanation:
In Oracle SQL, set operations like UNION, UNION ALL, INTERSECT, and MINUS can be used to combine results from different queries:
* Option A:
* Combining results using UNION ALL followed by ORDER BY will execute successfully because UNION ALL allows duplicate rows and ORDER BY can be used to sort the combined result set.
* Option E:
* Similar to option A, UNION ALL combines all rows from the two selects and allows ordering of the results.
* Option G:
* UNION combines the results from two queries and removes duplicates, and ORDER BY can be used to sort the final result set.
Options B, C, D, and F are incorrect because:
* Option B: You cannot intersect different columns (ORDER_ID with INVOICE_ID).
* Option C: Incorrect column names and syntax with ORDER BY.
* Option D: ORDER BY cannot be used before a set operator like INTERSECT.
* Option F: ORDER BY cannot be used directly after a MINUS operator without wrapping the MINUS operation in a subquery.

NEW QUESTION # 235
Which four statements are true about constraints on Oracle tables?

A. A UNIQUE constraint permits NULLS.
B. A UNIQUE Constraint can use a pre-existing index on the constrained column or columns.
C. A PRIMARY KEY Constraint can be added after a table has been created and populated.
D. A NOT NULL Constraint can be defined at the table level.
E. A FOREIGN KEY Column can contain NULLS.
F. A Column can have only one CHECK Constraint.
G. A CHECK Constraint can refer to values in other rows.

Answer: A,B,C,E

Explanation:
C: True. A UNIQUE constraint in Oracle SQL allows for the inclusion of NULL values; specifically, it permits multiple NULLs in a column or set of columns but ensures that all non-NULL values are unique.
D: True. A PRIMARY KEY constraint can indeed be added to a table after it has been created and even after it has been populated, as long as the existing data does not violate the primary key constraint rules (i.e., all values must be unique and not NULL).
F: True. A UNIQUE constraint can utilize a pre-existing index on the columns it covers. If a suitable index already exists, Oracle can use this index to enforce the constraint, optimizing performance and resource utilization.
G: True. Columns that are part of a FOREIGN KEY constraint can contain NULL values. This is permissible under SQL standards and Oracle implementation, as a NULL foreign key value is considered to not refer to any row in the referenced table and thus does not violate referential integrity.

NEW QUESTION # 236
See the Exhibit and examine the structure of the PROMOTIONS table:

Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:

What would be the outcome?

A. It generates an error because multiple conditions cannot be specified for the WHEN clause.
B. It executes successfully and gives the required result.
C. It generates an error because CASE cannot be used with group functions.
D. It generates an error because NULL cannot be specified as a return value.

Answer: B

Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END

NEW QUESTION # 237
Examine this statement:
SELECT last name
FROM employees
ORDER BY CASE WHEN salary = (SELECT MAX(salary) FROM employees)
THEN 'A'
ELSE last_ name
END ,last_name DESC;
Which two statements are true?

A. The names of employees earning the maximum salary will appear first In ascending order.
B. The names of employees earning the maximum salary will appear first in descending order.
C. All remaining employee names will appear in descending order.
D. All remaining employee names will appear in ascending order.
E. All remaining employee names will appear in an unspecified order.
F. The names of employees earning the maximum salary will appear first in an unspecified order.

Answer: C,F

NEW QUESTION # 238
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)

In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:

Which two JOIN operations can be used to obtain the required output? (Choose two.)

A. FULL OUTER JOIN
B. RIGHT OUTER JOIN
C. JOIN
D. LEFT OUTER JOIN

Answer: A,D

NEW QUESTION # 239
......

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